The value of `{(sqrt(2) +1)^(5) + (sqrt(2) -1)^(5)}` ,is

Using binomial theorem,expand {(x+y)^(5)+(x-y)^(5)}* and hence find the value of {(sqrt(2)+1)^(5)+(sqrt(2)-1)^(5)}

The value of (sqrt(5)+1)^(5)-(sqrt(5)-1)^(5) is ………

Using binomial theorem, expand {(x+y)^5+(x-y)^5}dot and hence find the value of {(sqrt(2)+1)^5+(sqrt(2)-1)^5}dot

The value of log_((sqrt(2)-1))(5sqrt(2)-7) is :

The value of log_((sqrt(2)-1))(5sqrt(2)-7) is :

Expand (sqrt 2 + 1)^5 - (sqrt 2 - 1)^5

Find the value of: (i) (sqrt 3 + 1)^4 - (sqrt 3 - 1)^4 (ii) (2 + sqrt 5)^5 + (2 - sqrt 5)^5

The value of {1/((sqrt(6) - sqrt(5))) + 1/((sqrt(5) + sqrt(4))) + 1/((sqrt(4) + sqrt(3))) - 1/((sqrt(3) - sqrt(2))) + 1/((sqrt(2) - 1))} is :

Find the value of (1/(sqrt(5) - 2) + 1/(sqrt(5) + 2))^(2) .