A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to 3 times the square of depth of the lake, the refractive index of water.

A point source of light is placed at the bottom of a water lake. If the area of the illuminated circle on the surface is equal to 3 times the square of the depth of the lake. The refractive index of water is

A source of light is placed at the bottom of a tank filled with water up to the height of 80 cm. Calculate the area at the surface of water through which light rays will be emitted. Refractive index of water = 1.33.

A point source of light is placed at a distance h below the surface of a large and deep lake. If f is the fraction of light energy that escapes directly from water surface and mu is refractive index of water then:

A point source of light is placed directly below the surface of a lake at a distance h from the surface. Find the area surface of a lake at a distance h from the surface. Find the area on water from which the light will come out from water. [(pih^(2))/((mu^(2)-1))]

A point source of light is placed at distance h below the surface of a large and deep lake. What fraction of light will escape through the surface of water?

A small bulb is placed at the bottom of a tank containing water to a depth of 80 cm. What is the area of the surface of water through which light from the bulb can emerge out? Refractive index of water is 1.33. (Consider the bulb to be a point source.)