Particles of masses `m_1` and `m_2` are at a fixed distance apart. If the gravitational field strength at `m_1` and `m_2` are `vec I_1` and `vec I_2` respectively. Then,

Particles of masses m_(1) and m_(2) are at a fixed distance apart. If the gravitational field strength at m_(1) and m_(2) are vecI_(1) and vecI_(2) respectively. Then

Particles of masses m_1 and m_2 are at a fixed distance apart . If the gravitational field strength at m_1 and m_2 are vecI_1 and vecI_2 respectively . Then ,

Two particle of mass m_1 and m_2 approach each other due to their mutual gravitational attraction only. Then

Two bodies of masses M_(1) and M_(2) , are placed at a distance R apart. Then at the position where the gravitational field due to them is zero, the gravitational potential is

The distance between two particles of masses m_(1)andm_(2) is r. If the distance of these particles from the centre of mass of the system are r_(1)andr_(2) respectively, then show that r_(1)=r((m_(2))/(m_(1)+m_(2)))andr_(2)=r((m_(1))/(m_(1)+m_(2)))

Two bodies of masses m_(1) and m_(2) ar placed at a distance r apart. Shows that the position where the gravitational field due to them is zer, the potential is given by V=-(G)/(r)"["m_(1)+m_(2)+2sqrt(m_(1)m_(2))"]"

Two bodies of masses m_(1) and m_(2) are placed at a distance r apart. Show that the position where the gravitational field due to them is zero, the potential is given by -G (m_(1) + m_(2) + 2 sqrt(m_(1) + m_(2)))//r