Fringe width equal to 1 mm is observed in the interference pattern of biprism experiment. Then the distance of nearest bright fringe from the central bright fringe will be :

The distance of n^(th) bright fringe from the centre of the interference pattern is

Calculate the semi angular width of the fifth bright fringe from the central fringe.

In a biprism experiment, the distance of the 7th dark band from the central bright band is 2.6 mm. the width of the fringe is

The distance of nth bright fringe to the nth dark fringe in Young's experiment is equal to

The distance of nth bright fringe to the nth dark fringe in Young's experiment is equal to

In Young's double slit experiment, the interference bright fringes are of:

In Young's double slit experiment, the distance between two coherent sources is 1 mm and the distance between the slits and the screen is 1 m. If the 10th dark fringe is at a distance of 4.75 mm from the central bright fringe, calculate the distance of 5th bright fringe from the central bright fringe.