The equilibrium constant for the gaseous reaction `H_(2)+Cl_(2)hArr2HCl` is given by

The reaction H_(2) + Cl_(2) to 2HCl is a

On a given condition, the equilibrium concentration of H, H_(2) and I_(2) are 0.80 , 0.10 and 0.10 mole/litre. The equilibrium constant for the reaction H_(2) + I_(2) hArr 2HI will be

On a given condition, the equilibrium concentration of HI , H_(2) and I_(2) are 0.80 , 0.10 and 0.10 mole/litre. The equilibrium constant for the reaction H_(2) + I_(2) hArr 2HI will be

The equilibrium constant for the reaction N_(2) + 3H_(2) hArr 2NH_(3) is 'K' . Then the equilibrium constant for the reaction 2N_(2) + 6H_(2) hArr 4NH_(3) will be

Unit of equilibrium constant for the reversible reaction H_(2) + I_(2)hArr 2HI is

The equilibrium constant for the reaction H_(2)+Br_(2)hArr2HBr is 67.8 at 300 K . The equilibrium constant for the dissociation of HBr is:

The equilibrium constant for the reaction H_(2)+Br_(2)hArr2HBr is 67.8 at 300(@)K . The equilibrium constant for the dissociation of HBr is:

the value of equilibrium constant for the reaction HI(g) hArr 1//2 H_(2) (g) +1//2 I_(2) (g) " is " 8.0 The equilibrium constant for the reaction H_(2) (g) +I_(2) (g) hArr 2HI(g) will be