The resistance in the two arms of the meter bridge are `5 Omega` and `R Omega`, respectively. When the resistance `R` is shunted with an equal resistance, the new balance point is `1.6 l_(1)`.
The resistance `R` is

The resistances in the two arms of the metre bridge are 5Omega and "R "Omega , respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6" "l_(1) . The resistance R, is

The resistances in the two arms of the mater bridge are 5Omega and ROmega , respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6l_(1) . The resistance 'R' is

The resistances in the two arms of the meter bridge are 5Omega and R Omega respectively. When the resistance R is shunted with an equal resistance, the new balance point is at 1.6l_(1) . The resistance 'R' is ----

The resistances in the two arms of the metre bridge are 5 Omega and R Omega respectively. When resistance R is shunted with an equal resistance, the new balance point is at 1.6 l_1 .The resistance R, is:

What is end error in a metre bridge ? How is it overcome ? The resistances in the two arms of the metre bridge are R=5Omega and S respectively. When the resistance S is shnted with an equal resistance, the new balance length forund to be 1.5 i_(1) , Where I_(1) is the initial balancing length. Calculate the value of S.

The resistances in the two arms of the metre bridge are R=5Omega and S respectively. When the resistance S is shnted with an equal resistance, the new balance length forund to be 1.5 i_(1) , Where I_(1) is the initial balancing length. Calculate the value of S.

The resistance in two gaps of a meter bridge are 10 Omega and 30 Omega respectively. If the resistances are interchanged the balance point shifts by