Time period of a charged particle undergoing a circular motion in a uniform magnetic field is independent of

The time period of a charged pawrticle undergoing a circular motion in a uniform magnetic field is independent of its

Force on a charge in electric and magnetic fields A charge particle follows a parabolic path in a uniform electric field and a charged particel moving in a uniform magnetic field has two kinds of motions lnear motion in the direction of magnetic field and circular motion in a plane perpendicular to the magnetic field. when charge q is moving perpendicular to the magnetic field B, the radius of the circular path is r=(mv)/(Bq) . If v and B makes an angle theta , then r=(mvsintheta)/(Bq) , and the time period T=(2pim)/(Bq) . The time period of a charged particle undergoing a circular motion in uniform magnetic field is independent of its

The path of a charged particle whose motion is perpendicular to a uniform magnetic field is

The time period of the charged particle circulating at right angles to a uniform magnetic field does not depend upon the

Assertion A charged particle is rotating in a circular path in uniform magnetic field. Then, plane of circle is perpendicular to the magnetic field. Reason Circular motion is a two-dimensional motion.

If a charged particle is a plane perpendicular to a uniform magnetic field with a time period T Then