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The percentage weight of Zn in which vit...

The percentage weight of Zn in which vitriol `[ZnSO_(4)*7H_(2)O]` is approximately equal to (at. Mass of Zn =65 , S= 32, O=16 and H=1)

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The percentage weight of Zn in white vitriol [ZnSO_(4)*7H_(2)O] is approximately equal to (at. Mass of Zn =65 , S= 32, O=16 and H=1)

White vitriol is ZnSO_(4).xH_(2)O .What is x ?

The percentage of zinc in ZnSO_(4) . 7H_(2)O is (Zn = 65, S = 32, O = 16 H= 1)