If a, b are the real roots of `x^(2) + px + 1 = 0` and c, d are the real roots of `x^(2) + qx + 1 = 0`, then `(a-c)(b-c)(a+d)(b+d)` is divisible by

a, b are the real roots of x2+ px +1-0 and c, d are the real roots of 2 x + qx + 1 = 0 then (a-c)(h-c)(a + d)(b + d) is divisible by n) a+b+c+d (b) a +b-c-d (d) a -b-c-d (c) a-b+c-d

If a, b are the roots of x^(2)+px+1=0 and c, d are the roots of x^(2)+qx+1=0 , show that q^(2)-p^(2)=(a-c)(b-c)(a+d) (b+d) .

If a,b are the roots of x^(2)+px+1=0 and c d are the roots of x^(2)+qx+1=0, Then ((a-c)(b-c)(a+d)(b+d))/(q^(2)-p^(2))

If a,b are roots of the equation x^(2)+qx+1=0 and c, dare roots of x^(2)+px+1=0, then the value of (a-c)(b-c)(a+d)(b+d) will be

If x_(1),x_(2) are the roots of ax^(2)+bx+c=0 and x_(1)+d,x_(2)+d are the roots of px_(2)+qx+r=0, where d!=0, then

If a,b,c,d in R-{0} , such that a,b are the roots of equation x^(2)+cx+d=0 and c,d are the roots of equation x^(2)+ax+b=0, then |a|+|b|+|c|+|d| is equal to

If a,b,c,d in R-{0} , such that a,b are the roots of equation x^(2)+cx+d=0 and c,d are the roots of equation x^(2)+ax+b=0, then |a|+|b|+|c|+|d| is equal to

For the equation |x^2|+|x|-6=0 , the sum of the real roots is (a) 1 (b) 0 (c) 2 (d) none of these

If a and b are roots of the equation x^2+a x+b=0 , then a+b= (a) 1 (b) 2 (c) -2 (d) -1

If a and b are roots of the equation x^2+a x+b=0 , then a+b= (a) 1 (b) 2 (c) -2 (d) -1