`int_0^(2a)f(x)dx` is equal to `2int_0^af(x)dx` b. `0` c. `int_0^af(x)dx+int_0^af(2a-x)dx` d. `int_0^af(x)dx+int_0^(2a)f(2a-x)dx`

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int_0^(2a)f(x)dx is equal to a. 2int_0^af(x)dx b. 0 c. int_0^af(x)dx+int_0^af(2a-x)dx d. int_0^af(x)dx+int_0^(2a)f(2a-x)dx

int_(0)^(2a)f(x)dx-int_(0)^(a)f(x)dx=

int_(0)^(2a)f(x)dx=int_(0)^(a)f(x)dx+int_(0)^(a)f(2a-x)dx .

int_(0)^(a)f(x)dx=int_(a)^(0)f(a-x)dx .

Prove that int_0^af(x)dx = int_0^af(a-x)dx

If int_(0)^(a) f(x) dx + int_(0)^(a) f(2a-x) dx =

int_0^af(a-x)dx =..... a) int_0^(2a)f(x)dx b) int_-a^af(x)dx c) int_0^af(x)dx d) int_a^0f(x)dx

Prove that: int_0^(2a)f(x)dx=int_0^(2a)f(2a-x)dxdot