For a system, `a+2BhArrC` , the equilibrium comcentrations are `[A]=0.06, [B]=0.12`, and `[C]=0.216`. The `K_(c )` for the reaction is

For a system A+2B hArr 2C the equilibrium concentration are [A]=0.06, [B] = 0.12 and [C]=0.216 The K_c for the reaction is :

For the system A(g)+2B(g) hArr C(g) the equilibrium concentration is A=0.06 mol L^(-1), B=0.12 mol L^(-1) C=0.216 mol L^(-1) The K_(eq) for the reaction is

For the system A(g)+2B(g) hArr C(g) the equilibrium concentration is A=0.06 mol L^(-1), B=0.12 mol L^(-1) C=0.216 mol L^(-1) The K_(eq) for the reaction is

For the system A (g) + 2 B (g) hArr C(g) the equilibrium concenrations are A =0.06 mol L^(-1) B = 0,12 mol L^(-1) C = 0.216 mol L^(-1) The K_(eq) for the reaction is

For the system 3A+2BhArrC , the expression for equilibrium constant K is