The value of `cos (270^(@) + theta) cos ( 90^(@) -theta) -sin (270^(@) - theta) cos theta ` is

Select and write the correct answer from the given alternatives in each of the following:The value of cos(270^@+theta).cos(90^@-theta)-sin(270^@-theta).costheta is=

The value of cos(270^@+theta)cos(90^@+theta)-sin(270^@-theta)costheta is.................. A) 0 B) -1 C) 1/2 D) 1

sin theta cos(90^(@)-theta)+cos theta sin(90^(@)-theta)

sin(270^(@)-theta).sin(90^(@)-theta)-cos(270^(@)-theta).cos(90^(@)+theta)=

Prove that sin (270^(@)-theta) sin (90^(@)-theta)-cos(270^(@)-theta) cos (90^(@)+theta)+1=0

sin theta cos(90^@ -theta) +cos theta sin(90^@ -theta) = ?

((cos (90 ^ (@)) - theta) sin (90 ^ (@) - theta)) / (tan (90 ^ (@) - theta))

Prove: (iii) "sec" (270^(@) - theta) "sec" (90^(@)- theta) - tan (270^@ - theta) tan (90^(@) + theta) = -1