A body with mass 5 kg is acted upon by a force `vec(F) = (- 3 hat (i) + 4 hat (j)) N`. If its initial velocity at t =0 is `vec(v) = 6 hat(i) - 12 hat (j) ms^(-1)`, the time at which it will just have a velocity along the y-axis is :

A force of (2.6 hat(i) + 1.6 hat(j)) N acts on a body of mass 2 kg. If the velocity of the body at time, t = 0 is (3.6 hat(i) - 4.8 hat(j)) ms^(-1) , the time at which the body will just have a velocity along x-axis only is

A body of mass 5 kg statrs from the origin with an initial velocity vec(u) = (30 hat(i) + 40 hat(j)) ms^(-1) . If a constant force (-6 hat(i) - 5 hat(j))N acts on the body, the time in which the y component of the velocity becomes zero is

A body of mass 5 kg statrs from the origin with an initial velocity vec(u) = (30 hat(i) + 40 hat(j)) ms^(-1) . If a constant force (-6 hat(i) - 5 hat(j))N acts on the body, the time in which they component of the velocity becomes zero is

A body of mass 5 kg statrs from the origin with an initial velocity vec(u) = (30 hat(i) + 40 hat(j)) ms^(-1) . If a constant force (-6 hat(i) - 5 hat(j))N acts on the body, the time in which they component of the velocity becomes zero is

The work done by the force vec( F ) = 6 hat(i) + 2 hat(j) N in displacing an object from vec( r_(1)) = 3 hat(i) + 8 hat( j) to vec( r_(2)) = 5 hat( i) - 4 hat(j) m , is

The work done by the force vec( F ) = 6 hat(i) + 2 hat(j) N in displacing an object from vec( r_(1)) = 3 hat(i) + 8 hat( j) to vec( r_(2)) = 5 hat( i) - 4 hat(j) m , is

If vec(F ) = (60 hat(i) + 15 hat(j) - 3 hat(k)) N and vec(V) = (2 hat(i) - 4 hat(j) + 5 hat(k)) m/s, then instantaneous power is:

If vec(F ) = (60 hat(i) + 15 hat(j) - 3 hat(k)) N and vec(V) = (2 hat(i) - 4 hat(j) + 5 hat(k)) m/s, then instantaneous power is:

An object of mass 3 kg is at rest. Now a force of vec F = 6 t^2 hat i + 4 t hat j is applied on the object, the velocity of object at t= 3 s is.