Home
Class 12
CHEMISTRY
The standard free energy change of a rea...

The standard free energy change of a reaction is `DeltaG^(@)=-115` at 298K. Calculate the equilibrium constant `K_(P)` in log `K_(P).(R=8.314JK^(-1)mol^(-1))`

Promotional Banner

Similar Questions

Explore conceptually related problems

The standard free energy change of a reaction is DeltaG^(@)=-115kJ//mol^(-1) at 298 K. Calculate the value of log_(10)K_(p) (R=8.314JK^(-1)mol^(-1))

The standard free energy change of a reaction is DeltaG^(@)=-115kJ//mol^(-1) at 298 K. Calculate the value of log_(10)K_(p) (R=8.314JK^(-1)mol^(-1))

The standard free energy change of a reaction is DeltaG^(@)=-kJ//mol^(-1) at 298 K. Calculate the value of log_(10)K_(p) (R=8.314JK^(-1)mol^(-1))

The standard free energy of the reaction at 298K is -125.52 kJ/mole. Calculate the equilibrium constnat K_(p) .

Standard free energy change of a reaction is +150 kJ mol^(-1) . Calculate K_(p) at 30^(@)C .

Calculate the standard free energy change for a reaction at 273K, if the equilibrium constant of the reaction at 273K is 20

The standard free energy change DeltaG^(@) is related to k (equilibrium constant) as