A ball of mass 1 kg is projected with `10ms^(-1)` froom the top of a toer of height 20 m. What is its speed when it is at vertical distance of 10 m below point of projection? `(g=10ms^(-2))`

A ball of mass 1 kg is projected with 10ms^(-1) from the top of a tower of height 20 m. What is its speed when it is at vertical distance of 10 m below point of projection? (g=10ms^(-2))

A ball is projected horizontally with a velocity of 5 ms^(-1) from the top of a tower of height 10 m. When it reaches the ground (g=10 ms^(-2) )

Two particles of same mass are project simultaneously with same speed 20ms^(-1) from the top of a tower of height 30m. One is projected vertically upwards and other projected horizontally.The maximum height attained by centre of mass from the ground will be (g=10ms^(-2))