Periodic time of a satellite revolving above Earth's surface at a height equal to R, radius of Earth, is : [g is acceleration due to gravity at Earth's surface]

At a height equal to earth's radius, above the earth's surface, the acceleration due to gravity is

A satellite is in a circular orbit round the earth at an altitude R above the earth's surface, where R is the radius of the earth. If g is the acceleration due to gravity on the surface of the earth, the speed of the satellite is

A particle is taken to a height R above the earth's surface, where R is the radius of the earth. The acceleration due to gravity there is

An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by

An earth satellite of mass m revolves in a circular orbit at a height h from the surface of the earth. R is the radius of the earth and g is acceleration due to gravity at the surface of the earth. The velocity of the satellite in the orbit is given by

A satellite of mass m is revolving around the earth at a height x above the surface of the earth. The radius of the earth is R. If the acceleration due to gravity is g, the orbital speed of the satellite will be

A satellite of mass m is moving in a circular or orbit of radius R around the earth. The radius of the earth is r and the acceleration due to gravity at the surface of the earth is g. Obtain expressions for the following : (a) The acceleration due to gravity at a distance R from the centre of the earth (b) The linear speed of the satellite (c ) The time period of the satellite