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For a system in equilibrium, DeltaG=0, u...

For a system in equilibrium, `DeltaG=0`, under conditions of constant

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The change in Gibbs free energy of the system alone provides a criterion for the spontaneity of a process at constant temperature and pressure. A change in the free energy of a system at constant temperature and pressure will be : DeltaG_("system")=DeltaH_("system")-T DeltaS_(system") For a system in equilibrium, DeltaG=0 , under conditions of contant....

For a system in equilibrium Delta G= 0 under conditions of constant:

For a system in equilibrium, /_\G = 0 under conditions of constant ......

A reaction attains equilibrium state under standard conditions, then:

A reaction attains equilibrium state under standard conditions, then:

Delta G = O at equilibrium is satisfied under condition

A reaction attains equilibrium state under standard conditions, then A) equilibrium constant K=0 B) equilibrium constant "K=1 C) Delta G^(o)=0 and Delta H^(o)=T Delta S^(o) D) Delta G=0 and Delta H = T Delta S

DeltaG of the system alone provides a criterion for the spontaneity of a process at constant temperature & pressure, DeltaG system lt 0 (spontaneous) DeltaG system = 0 (equilibrium) DeltaG system gt 0 {(non-spontaneous) Again DeltaG^@ is related to the equilibrium constant as follows : DeltaG^@ = 2.303 RT log K_e If both DeltaH and Delta S are negative, the reaction will be spontaneous