Find `(dy)/(dx)` , when `x=a\ (costheta+thetasintheta)` and `y=a(sintheta-thetacostheta)`

If x and y are connected parametrically by the equations given, without eliminating the parameter, Find (dy)/(dx) . x=a(costheta+thetasintheta), y=a(sintheta-thetacostheta)

Find dy/dx , when: x=a(1-costheta),y=a(theta+sintheta)

Find (dy)/(dx) , if x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)

Find dy/dx of x=a(costheta+thetasintheta) , y=a(sintheta-thetacostheta)

Find (dy)/(dx) when : x=a(1+costheta),y=a(theta+sintheta) .

Find (dy)/(dx) when y=x^y .

If x=a(costheta+thetasintheta),y=a(sintheta-thetacostheta)," then "(dy)/(dx)=

Find dy/dx when x = a(1 + costheta) , y= a(theta-sintheta)

Find (dy)/(dx), when x=a e^(theta)(sintheta-costheta),y=a e^(theta)(sintheta+costheta)