If `veca` and `vecb` are two unit vectors and the angle between them is `60^(@)` then `((1+veca.vecb))/((1-veca.vecb))` is

If veca and vecb are unit vector and theta is the angle between then, then |(veca - vecb)/2| is:

If veca,vecb are unit vectors and theta is the angle between them, show that tan""(theta)/(2)=(|veca-vecb|)/(|veca+vecb|)

Let veca and vecb be two unit vectors and theta is the angle between them. Then veca+vecb is a unit vector if:

Let veca and vecb be two unit vectors and theta is the angle between them. Then veca+vecb is a unit vector if :

Let veca and vecb be two unit vectors and alpha be the angle between them, then veca + vecb is a unit vector , if alpha =

Let veca and vecb be two unit vectors and alpha be the angle between them, then veca + vecb is a unit vector , if alpha =

Let veca and vecb be two vectors of the same magnitude such that the angle between them is 60^(@) and veca.vecb =8. Find |veca| and |vecb| .