If 20 cc. of HCl solution is exactly neutralised by 40 cc of 0.05 N NaOH, then pH of HCl is

20 cc of 'x' M HCl is exactly neutralised by 40 cc of 0.05 M NaOH . The pH of HCl solution is

20 cm^(3) of xM solution of HCl is exactly neutralised by 40cm^(3) of 0.05 M NaOH solutions, the pH of HCl solution is

20 cm^(3) of xM solution of HCI is exactly neutralised by 40cm^(3) of 0.05 M NaOH solutions, the pH of HCI solution is

If 20 mL of 0.4 N NaOH solution completely neutralised 40 mL of a dibasic acid, the molarity of the acid solution is

If 20 mL of 0.4 N NaOH solution completely neutralises 40 mL of a dibasic acid, the molarity of the acid solution is :

If 20ml of 0.4 N NaOH solution completely neutralise 40ml of a dibasic acid, the molarity of the acid solution is:

The pH of the neutralisation point of 0.1 N NaOH with 0.1 N HCl is