`"I f"I_1=int_(-100)^(101)(dx)/((5+2x-2x^2)(1+e^(2-4x)))` `"and"I_2=int_(-100)^(101)(dx)/(5+2x-2x^2),t h e n(I_1)/(I_2)"i s"` 2 (b) `1/2` (c) 1 (d) `-1/2`

"I f"I_1=int_(-100)^(101)(dx)/((5+2x-2x^2)(1+e^(2-4x))) "and"I_2=int_(-100)^(101)(dx)/(5+2x-2x^2),t h e n(I_1)/(I_2)"i s" (a)2 (b) 1/2 (c) 1 (d) -1/2

"I f"I_1=int_(-100)^(101)(dx)/((5+2x-2x^2)(1+e^(2-4x))) "and"I_2=int_(-100)^(101)(dx)/(5+2x-2x^2),t h e n(I_1)/(I_2)"i s" (a)2 (b) 1/2 (c) 1 (d) -1/2

"I f"I_1=int_(-100)^(101)(dx)/((5+2x-2x^2)(1+e^(2-4x))) "and"I_2=int_(-100)^(101)(dx)/(5+2x-2x^2),t h e n(I_1)/(I_2)"i s" (a)2 (b) 1/2 (c) 1 (d) -1/2

If I_(1)=int_(-100)^(101)(dx)/((5+2x-2x^(2))(1+e^(2-4x))) and I_(2)=int_(-100)^(101)(dx)/(5+2x-2x^(2)) , then I_(1)//I_(2) is a)2 b) 1/2 c)1 d) -1/2

If I_1 = int_(-100)^(101) dx/((5+2x-2x^2)(1+e^(2-4x)) and I_2= int_(-100)^(101) dx/(5+2x-2x^2), then I_1/I_2 is (a) 2 (b) 1/2 (c) 1 (d) -1/2

If I_(1)=int_(-100)^(101)(dx)/((5+2x-2x^(2))(1+e^(2-4x))) and quad I_(2)=int_(-100)^(101)(dx)/(5+2x-2x^(2)), then (I_(1))/(I_(2)) is 2(b)(1)/(2) (c) 1 (d) -(1)/(2)

If I_(1)=int_(0)^(oo) (dx)/(1+x^(4))dx and I_(2)=underset(0)overset(oo)int x^(2)(dx)/(1+x^(4))"then"n (I_(1))/(I_(2))=

Let I_(1)=int_(1)^(2)(x)/(sqrt(1+x^(2)))dx and I_(2)=int_(1)^(2)(1)/(x)dx .Then

If I_(1)=int_(0)^(1)(e^(x))/(1+x)dx aand I_(2)=int_(0)^(1)(x^(2))/(e^(x^(3))(2-x^(3)))dx then (I_(1))/(I_(2)) is