The central atom of a molecule has `33%` s-character in its hybrid orbitals. Its geometry will be :

With increase in 's' character of hybrid orbital

As the s-character of a hybrid orbital increases the bond angle

The % of p character in hybrid orbital of the central atom of water molecule

The % of 'p' character in hybrid orbital of the central atom of water molecule

The percentage of S-character in Sp^2 hybrid orbital is----------.

The sp^3d^2 hybridization of central atom of a molecule would lead to: square planar geometry, tirgonal bipyramidal geometry, tetrahedral geometry, octahedral geometry

Two hybrid orbitals have a bond angle of 120^(@) . The percentage of s-character in the hybrid orbitals is nearly:

The correct order of increasing s-character (in percentage) in the hybrid orbitals of following molecules/ions is :- (A) CO_(3)^(-2) " "(B) NCl_(3)" "(C ) BeCl_(2)