If `x(dy)/(dx)=y(log y -logx+1),` then the solution of the equation is

If x(dy)/(dx)=y(logy-logx+1), then the solution of the equation is :

If x(dy)/(dx) = y (log y - log x +1) , then the solution of the equation is

If x(dy)/(dx)=y(log_(e)y-log_(e)x+1) ,then solution of the equation is

If x dy/dx=y(logy-logx+1) , then the solution of the differential equation is (A) log(x/y)=Cy (B) log(y/x)=Cy (C) log(x/y)=Cx (D) log(y/x)=Cx

The solution of the equation log ((dy)/(dx))=a x+b y is