`{:("Given",K,L,M,N,),(,2,8,11,2,):}`
The number of electrons present in `l=2` is -

Given is the electronic configuration of element X {:(K,L,M,N,),(2,8,11,2,):} The number of electrons present with l = 2 in an atom of element X is.

Calculate the total number of electrons for n=3,l=2 and m=-2

Calculate the total number of electrons for Mn having n+l+m=2

An atom has 2 electrons in K shell, 8 electrons in L shell and 6 electrons in M shell. The number of s-electrons present in that element is

In Se(Z = 34) how many electrons are present with m_(l) = 2 ?

In Se(Z = 34) how many electrons are present with m_(l) = 2 ?

In an atom the number of electrons in M - shell is equal to the number of electrons in the K and L - shell . Answer the question. Explanation : 1) Number of electrons in K-shell (1 s^(2)) = 2 Number of electrons in L-shell (2s^(2) sp^(6)) = 8 Total number of electrons in k & L shells = 10 2) Given that number of electrons in M-shell is equal to number of electrons in K& L- shells 3) Hence number of electrons in M-shell (3s^(2) 3p^(6) 3d^(2)) = 10 4) But , we know that before filling of 3d orbital 4s should be filled (4s^(2)) 5) So , electronic configuration is 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 4s^(2) 3d^(2) What is the atomic number of element ?