सिद्ध कीजिए कि
`(cos6theta-cos4theta)/(sin6theta+sin4theta)=-tantheta`.

(cos6 theta-cos4 theta)/(sin6 theta+sin4 theta)=-tan theta

int(2sin2 theta-cos theta)/(6-cos^(2)theta-4sin theta)d theta

Show that ((cos theta - cos 3theta)(sin 8theta + sin 2 theta))/((sin 5 theta - sin theta)(cos 4 theta - cos 6 theta)) = 1

Show that [(costheta -cos3theta)(sin8theta+sin2theta)]/[(sin5theta -sintheta)(cos4theta-cos6theta)]=1 .

Show that ((cos theta - cos 3 theta) (sin 8 theta + sin 2 theta))/((sin 5 theta - sin theta) (cos 4 theta- cos 6 theta))=1

Prove that ((cos theta-cos 3 theta)(sin 8 theta +sin 2 theta))/((sin 5 theta-sin theta)(cos 4 theta-cos 6 theta))=1

Show that :((cos theta-cos3 theta)(sin8 theta+sin2 theta))/((sin5 theta-sin theta)(cos4 theta-cos6 theta))=1

2(sin^6theta+cos^6theta)-3(sin^4theta+cos^4theta) is equal to

1 + (cos 2 theta + cos 6 theta)/(cos 4 theta) = (sin 3 theta)/(sin theta).

int(sin^(6)theta+cos^(6)theta)/(sin^(2)theta cos^(2)theta)d theta=