A wire of length l has a resistance R. If half of the length is stretched to make the radius half of its original value, then the final resistance of the wire is

A wire has a resistance of 32Omega . It is melted and drawn into a wire of half of its original length. What is the resistance of the new wire?

If a wire of resistance R is stretched to twice its original length, the new resistance of the wire will be:

A wire of length l is drawn such that its diameter is reduced to half of its original diameter. If the initial resistance of the wire were 10Omega , its new resistance would be

A wire of length l is drawn such that its diameter is reduced to half of its original diameter. If the initial resistance of the wire were 10Omega , its new resistance would be

A wire of length l is drawn such that its diameter is reduced to half of its original diameler. If the initial resistance of the wire were 10Omega . its resistance would become

A wire of length l is drawn such that its diameter is reduced to half of its original diameter. If the initial resistance of the wire were 10 Omega , its resistance would be

A wire of resistance R is stretched to three times its original length. The new resistance is

A resistance 10 Omega is stretched to twice its original length . The resistance of half of the stretched wire is