If `x= a sin 2theta (1+ cos 2theta)`, `y= b cos 2theta(1- cos 2theta)`, then `(dy)/(dx)`=

x=a sin2 theta(1+cos2 theta), y=b cos2 theta(1-cos2 theta) then (dy)/(dx)=

If x = a Sin 2 theta (1+Cos2 theta) , y = b Cos2 theta (1-Cos2 theta) , then (dy)/(dx) =

If x=a sin2 theta(1+cos2 theta) and y=b cos2 theta(1-cos2 theta), then prove that (dy)/(dx)=(b)/(a)tan theta

If x = cos theta (1 + cos theta ), y = sin theta (1 + cos theta ) show that ((dy)/(dx)) _(theta = ( pi )/(2)) =1.

If =a sin2 theta(1+cos2 theta),y=b cos2 theta(1-os2 theta)x=a sin2 theta(1+cos2 theta),y=b cos2 theta(1-os2 theta) and (dy)/(dx)=k tan theta then the value of k is

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =

If x=2 cos theta- cos 2 theta and y=2 sin theta - sin 2 theta, then (dy)/(dx) =