For a reaction `A+BrarrP` , the rate is given by Rate `=k[A][B]^(2)`
How is the rate of reaction affected if the concentration of B is doubled ?

(a) For a reaction A+BrarrP, the rate is given by Rate =K[A][B]^(2) (i) How is the rate of reaction affected if the concentration of B is doubled ? (ii) What is the overall order of reaction if A is present in large excess ? (b) A first order reaction takes 30 minutes for 50% completion. Calculate the time required for 90% completion of this reaction.

For a reaction A+B rarr P , the rate is given by - Rate = [A][B]^2 How is the rate of reaction affected if the concentration of B,is doubled?

For a reaction: A+ B rarr P , the rate law is given as: Rate = k[A][B]^2 How is the rate of reaction affected when the concentration of B is doubled?

For the reaction A + B rarr P , the rate is given by Rate = K [A]^(1) [B]^(2) . By how many times does the rate of reaction increase when concentrations of A & B are doubled?

The rate law for a certain reaction is found to be : Rate = k[A] [B]^(2) How will the rate of this reaction compare if the concentration of A is doubled and the concentration of B is halved ? The rate will :

The rate law for a reaction of A, B and C has been found to be rate = k [A][B][C]^2 . How would the rate of reaction change when concentration of both B and C are doubled ?

The rate law for a reaction between A and B is given by rate = k[A]^(n)[B]^(m) . On doubling the concentration of A and halving the concentration of B , the ratio of the new rate to the earlier rate of the reaction becomes

The rate law for a reaction between A and B is given by rate = k[A]^(n)[B]^(m) . On doubling the concentration of A and halving the concentration of B , the ratio of the new rate to the earlier rate of the reaction becomes