अनुक्रमों का वांछित पद ज्ञात कीजिए, जिनका n वां पद दिया गया है :
`a_(n)=(-1)^(n-1)n^(3), a_(9)`

If a_(n) = (n)/(n+1) , then a_(2017) = ………..

B={a_(n):n in N,a_(n)+1=2a_(n) and a_(1)=3}

समांतर श्रेणी का n वा पद -उदाहरण सहित |समांतर श्रेणी का अंत से n वा पद

If quad 1,a_(1)=3 and a_(n)^(2)-a_(n-1)*a_(n+1)=(-1)^(n) Find a_(3).

Find a_(1) and a_(9) if a_(n) is given by a_(n) = (n^(2))/(n+1)

Find a_(1) and a_(9) if a_(n) is given by a_(n) = (n^(2))/(n+1)

Find a_(1),a_(2),a_(3) if the n^(th) term is given by a_(n)=(n-1)(n-2)(3+n)

If a_(n) = 3-4n , then what is a_(1)+a_(2)+a_(3)+…+a_(n) equal to ?

Find a_(3),a_(5),a_(8) if the n^(th) term is given by a_(n)=(-1)^(n)n

Let a_(1),a_(2),a_(3), . . .,a_(n) be an A.P. Statement -1 : (1)/(a_(1)a_(n))+(1)/(a_(2)a_(n-1))+(1)/(a_(3)a_(n-1))+ . . .. +(1)/(a_(n)a_(1)) =(2)/(a_(1)+a_(n))((1)/(a_(1))+(1)/(a_(2))+ . . .. +(1)/(a_(n))) Statement -2: a_(r)+a_(n-r+1)=a_(1)+a_(n)" for "1lerlen