sin^(4)theta-cos^(4)theta=sin^(2)theta-cos^(2)theta

Prove that sin^4theta-cos^4theta=sin^2theta-cos^2theta .

sin^(4)theta+cos^(4)theta=1-2sin^(2)theta cos^(2)theta

Evaluate : 2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta)+4(sin^(2)theta+cos^(2)theta)

sin^(4)theta+sin^(2)theta cos^(2)theta=

The value of (2(sin^(6)theta+cos^(6)theta)-3(sin^(4)theta+cos^(4)theta))/(cos^(4)theta-sin^(4)theta-2cos^(2)theta) is :

Prove the following sin^4theta-cos^4theta=sin^2theta-cos^2theta=1-2cos^2theta=2sin^2theta-1

Prove that : sin^(2)theta+cos^(4)theta=cos^(2)theta+sin^(4)theta

Prove that : sin^(2)theta+cos^(4)theta=cos^(2)theta+sin^(4)theta

(sin^4theta-cos^4theta)/(sin^2theta-cos^2theta) = ………………..