`f(x)=1`, if x rational,
`=0,` if x is irrational. Then `(f(1//2)+f(sqrt5))/((fof)(sqrt3))=`

Let f(x)=[x^(2) if x is irrational,1 if x is rational then

f(x)={1 if x is rational then -1 if x is irrational then Lt_(x rarr1+f(x))=

If f(x)={x,x is rational 1-x,x is irrational , then f(f(x)) is

If f(x)={x ,x is rational 1-x ,x is irrational ,then f(f(x)) is

If f(x)={x ,x is rational 1-x ,x is irrational ,then f(f(x)) is

If f(x)={x ,x is rational 1-x ,x is irrational ,then f(f(x)) is

If f(x)={{:(1,"x is rational"),(2,"x is irrational"):} then

f(x)=1 for x is rational -1 for x is irrational,f is continuous on

If f:[0,1]to[0,1] is defined by f(x)={{:(x," if x is rational"),(1-x," if x is irrational"):} , then (fof)(x) is