A triangle ABC laying in the first quadrant has two vertices as A(1 , 2) B(3 , 1). If , `angle BAC=90^@` and ar `(DeltaABC)=5sqrt5` sq. units , then the abscissa of the vertex C is :

In DeltaABC, A=(1,2), B=(5, 5), angleACB=90^(0) . If area of DeltaABC is to be 6.5 sq. units, then the possible number of points for C is

In DeltaABC, A=(1,2), B=(5, 5), angleACB=90^(0) . If area of DeltaABC is to be 6.5 sq. units, then the possible number of points for C is

If two vertices of a triangle are (1,3) and (4,-1) and the area of triangle is 5 sq. units, then the angle at the third vertex lies in :

If two vertices of a triangle are (1,3) and (4,-1) and the area of triangle is 5 sq. units, then the angle at the third vertex lies in :

If two vertices of a triangle are (1,3) and (4,-1) and the area of triangle is 5 sq. units, then the angle at the third vertex lies in :

If two vertices of a triangle are (1,3) and (4,-1) and the area of triangle is 5 sq. units, then the angle at the third vertex lies in :

If two vertices of a triangle are (1,3) and (4,-1) e and the area of triangle is 5 sq.units,then the angle at the third vertex lies in:

The slope of a median, drawn from the vertex A of the triangle ABC is -2. The co-ordinates of vertices B and C are respectively (-1, 3) and (3, 5). If the area of the triangle be 5 square units, then possible distance of vertex A from the origin is/are.

The slope of a median, drawn from the vertex A of the triangle ABC is -2. The co-ordinates of vertices B and C are respectively (-1, 3) and (3, 5). If the area of the triangle be 5 square units, then possible distance of vertex A from the origin is/are.

If, in DeltaABC, a = sqrt(2), b = sqrt(3), c = sqrt(5) , then the area of Delta ABC is