`H_(2(g)) + I_(2(g))hArr2HI_((g))`
` Delta H = + q` cal, the formation of HI:

In an equilibrium reaction H_(2)(g) + I_(2)(g)hArr2HI(g) Delta H = - 3000 calories, Which factor favours dissociation of HI

H_(2)(g) + I_(2) hArr 2HI(g): Delta H = 12.40 kcal . According to this reaction, heat of formation of HI will be

If H_2(g) +I_2(g) rarr 2HI(g), Delta H=12.40 kcal . The enthalpy of formation of HI is

For H_2(g)+I_2(g)⇌2HI(g) , triangle H=12.4 K cal . The enthalpy of formation of HI is:

1 mole each of H_(2)(g) "and" I_(2)(g) are introduced in a 1L evacuated vessel at 523K and equilibrium H_(2)(g)+I_(2)(g)hArr2Hi(g) is established. The concentration of HI(g) at equilibrium: