In a binomial distribution consisting of 5 independent trials, probabilities of 1 and 2 successes are `0.4096 " and " 0.2048` respectively. Find the parameter p of the distribution.

In a binomial distribution consisting of 5 independent trials the probability of 1 and 2 sucesses are 0.4096 and 0.2048 respectively. Find the mean and variance of the distribution .

In a binomial distrubution consisting of 5 independent trials the probability of 1 and 2 successers are 0.4096 and 0.2048 respectively find the mean and variance of the random variable

Let in a Binomial distribution, consisting of 5 independent trials, probalitiies of exactly 1 and 2 sucesses be 0.4096 and 0.2048 resepectively. Then the probability of getting exactly 3 sucesses is equal to :

In binomial distribution with five Bernoulli's trails,probability of one and two success are 0.4096 and 0.2048 respectively.Find probability of success.

For a binomial distribution, if mean is 8 and variance is 6, then the probability of atleast 1 success is.

In a binomial distribution the sum and difference of mean and variance are 1.8 and 0.2 respectively. Find the parameters.