The foot of the perpendicular from (0, 0) to the line `x cos alpha+y sin alpha=p` is

Coordinates of the foot of the perpendicular drawn from 0,0 to he line jolning (a cos alpha,a sin alpha) and (a cos beta,a sin beta) are

The length of the perpendicular from the point (a cos alpha, a sin alpha) upon the line y=x tan alpha+c, c le 0, is

The point P is the foot of the perpendicular from A(0, t) to the line whose equation is y=tx . Determine the co-ordinates of P

If the foot of the perpendicular from (-4,5) to the straight line 3x-4y-18=0 is (alpha,beta) then value of (alpha+beta)=

The length of the perpendicular from the origin on the line (x sin alpha)/(b ) - (y cos alpha)/(a )-1=0 is

Find the length of perpendicular from the point (a cos alpha, a sin alpha) to the line x cos alpha+y sin alpha=p .