Express each of the following as a product: `sin4theta+sin2theta` (ii) `sin6theta-sin2theta` (iii) `cos4theta+cos8theta` (iii) `cos6theta-cos8theta`

Express each of the following as a product: sin4 theta+sin2 theta( ii) sin6 theta-sin2 theta( iii) cos4 theta+cos8 theta( iii) cos6 theta-cos8 theta

Express each of the following as a product: (i) sin4theta+sin2theta (ii) sin6theta-sin2theta (iii) cos4theta+cos8theta (iv) cos6theta-cos8theta

Express each of the following products into sum and difference of sines and cosines ( i ) 2cos3 theta sin2 theta( ii) 2sin5 theta cos3 theta( iii) cos9 theta cos4 theta(iv)sin75^(@)cos15^(@)

(3+cos4 theta)cos2 theta=4(cos^(8)theta-sin^(8)theta)

(cos theta + sin theta )/( cos theta - sin theta )-(cos theta - sin theta )/( cos theta + sin theta ) =

Prove each of the following identities : (i) (sin theta - cos theta)/(sin theta + cos theta) + ( sin theta+ cos theta)/(sin theta - cos theta) = (2)/((2 sin^(2) theta -1)) (ii) (sin theta + cos theta ) /(sin theta - cos theta) + ( sin theta - cos theta) /(sin theta + cos theta) = (2) /((1- 2 cos^(2) theta))

8sin theta cos theta cos2 theta cos4 theta=sin x rArr x=

(((cos theta+sin theta)^(4)-(cos theta-sin theta)^(4))/(sin theta cos theta))=?

((cos theta - cos 3 theta ) ( sin 8 theta + sin 2 theta ))/(( sin 5 theta - sin theta )( cos 4 theta - cos 6 theta ))=

Show that [(costheta -cos3theta)(sin8theta+sin2theta)]/[(sin5theta -sintheta)(cos4theta-cos6theta)]=1 .