If `: cot theta + cot((pi)/4 + theta) = 2`, then : `theta` =

If cot theta = sin 2 theta and theta != n pi , then : theta =

If tan(picos theta) = cot(pisin theta) , then cos(theta - pi/4) is :

If cosec theta - cot theta = 4, then cosec theta + cot theta =…………..

I : If sin((pi)/(4)cot theta)=cos ((pi)/(4)tan theta) then theta = n pi+pi//4, n in Z II : If tan ((pi)/(2)sin theta)=cot((pi)/(2)cos theta) then sin (theta + (pi)/(4))= pm (1)/(sqrt(2))

If "cot" theta "cot" 7 theta + "cot" theta "cot" 4 theta + "cot" 4 theta "cot" 7 theta = 1, " then" theta =

If "cot" theta "cot" 7 theta + "cot" theta "cot" 4 theta + "cot" 4 theta "cot" 7 theta = 1, " then" theta =

Prove that: cot theta cot2 theta + cot2 theta cot 3 theta + 2 = cot theta(cot theta - cot3 theta)

Prove that cot theta cot 2 theta+ cot 2 theta cot 3 theta+ 2= cot theta (cot theta- cot 3 theta) .

Number of solutions of the equation cot( theta ) + cot( theta +(pi)/(3))+ cos ( theta -(pi)/(3))+ cot( 3 theta ) =0 , where theta in ( 0,(pi)/(2))