`H_(2) (g) +I_(2) (g) rarr 2HI (g), DeltaH=51.9 kJ`.
According to this, heat of formation of `HI` is

H_(2)(g) + I_(2) hArr 2HI(g): Delta H = 12.40 kcal . According to this reaction, heat of formation of HI will be

Reaction, H_(2)(g)+I_(2)(g)to2HI,DeltaH=12.40kcal ltbr. According to this, heat of formation of HI will be:

If H_2(g) +I_2(g) rarr 2HI(g), Delta H=12.40 kcal . The enthalpy of formation of HI is

H_(2)(g)+I_(2) (s) rarr 2HI (g), DeltaH=51.9 KJ/mole H_(2)(g)+I_(2)(g) rarr 2 HI (g), DeltaH=-9.2 kJ/mole. the heat of reaction of I_(2)(s) rarr I_(2) (g)

F_(2)(g) +2HCI(g) rarr 2HF(g) +CI_(2)(g), DeltaH^(Theta) =- 352.18 kJ Given heat of formation of HF, Delta_(f)H^(Theta)underset((HF))" =- 268.3 kJ The heat of formation of HCI will be

F_(2)(g) +2HCI(g) rarr 2HF(g) +CI_(2)(g), DeltaH^(Theta) =- 352.18 kJ Given heat of formation of HF, Delta_(f)H^(Theta)underset((HF))" =- 268.3 kJ The heat of formation of HCl will be

H_2(g)+I_2(g)rarr2HI(g), triangleH=-12.40 kcals , Heat of formation of HI will be