(dy)/(da)=tan^(2)(x+y

(dy)/(dx)=tan^(2)(x+y)

The solution of (dy)/(dx) = tan^(2)(x+y) is

y^(2)-(dy)/(dx)=x^(2)(dy)/(dx) A) y^(-1)+tan^(-1)x=c B) x^(-1)+tan^(-1)y=c C) y+tan^(-1)x=c D) x^(-1)+y^(-1)=tan^(-1)x+c

(dy) / (dx) = tan ^ (2) (x + y)

(dy)/(dx) = y tan x - 2 sinx

If log (x^(2)+y^(2))=tan^(-1)((y)/(x)), then show that (dy)/(dx)=(x+y)/(x-y)

solved the differential equation tan y(dy)/(dx)+tan x=cos y cos^(2)x

(dy)/(dx)=(y)/(x)-tan""(y)/(x)