[" The work done in sliding a wooden box of mass "5kg],[" along a friction less inclined plane of inclination "30^(@)],[" and length "10m" is "quad J*(g=10ms^(-2))]

The work done in sliding a wooden box of mass 5 kg along a friction less inclined plane of inclination 30^(@) and length 10 m is ______J. (g=10 m s^(-2))

An object of mass m=1 kg is sliding from top to bottom in the frictionless inclined plane of inclination angle theta = 30^(@) and the length of inclined plane is 10m as shown in the figure. Calculate the work done by gravitational force and normal force on the object Assume acceleration due to gravity, g=10ms^(-2)

The work done in pulling a body of mass 5 kg along an inclined plane (angle 60^(@) ) with coefficient of friction 0.2 through 2 m, will be -

A block of mass 5.0 kg slides down an incline of inclination 30^0 and length 10 m. find the work done by the force of gravity.

A block of mass 5.0 kg slides down an incline of inclination 30^0 and length 10 m. find the work done by the force of gravity.

The work done in moving a body of mass 5kg from the bottom of a smooth inclined plane to the top is 50 j. If the angle of inclination of the inclined plane is 30^(@) , its length is (g = 10 ms^(-2))

500 J of work is done in sliding a 4 kg block up along a rough inclined plane to a vertical height of 10 m slowly. The work done against friction is (g = 10 m/s^2)