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What is the elctric flux through a cube of side 1 cm which encloses on electric dipole ?

What is the electric flux through a cube of side 1 cm which encloses an electric dipole ?

Electric field in a region is given by vec( E) = - 4xhat(i) + 6yhat(j) . Then find the charge enclosed in the cube of side 1m oriented as shown in the diagram

The electric potential V("x") in a region around the origin is given by V"(x)" = 4x^(2) volts. The electric charge enclosed in a cube of 1 m side with its centre at the origin is (in coulomb

Electric field in a region is given by vec(E)=-4xhat(i)+6yhat(j) . The charge enclosed in the cube of side 1 m oriented as shown in the diagram is given by alpha in_(0) . Find the value of alpha .

Electric field in a region is given by vec(E)=-4xhat(i)+6yhat(j) . The charge enclosed in the cube of side 1 m oriented as shown in the diagram is given by alpha in_(0) . Find the value of alpha .