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A scientist is weighing each of 30 fishe...

A scientist is weighing each of 30 fishes. Their mean weight worked out is 30 gm and a standard deviation of 2 gm. Later, it was found 20.that the measuring scale was misaligned and always under reported every fish weight by 2 gm. The correct mean and standard deviation(in gm) of fishes are respectively (a) `28,4` (b) `32,2` (c) `32,4` (d) `28,2`

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A scientist is weighing each of 28 fishes. Their mean weight worked out is 28 gm and a standard deviation of 2 gm . Later, it was found that the measuring scale was misaligned and always under reported every fish weight by 4gm. The correct mean and standard deviation (in gm) of fishes are respectively :

The mean and standard deviation of 20 observations are found to be 10 and 2 respectively.One rechecking,it was found that an observation 8 was incorrect.Calculate the correct mean and standard deviation in each of the following cases.(i) If wrong item is omitted (ii) If it is replaced by 12.

The mean and standard deviation of 6 observations are 8 and 4 respectively . If each observation is multiplied by 2, find the new mean and new standard deviation of the resulting observation.

The standard deviations of two sets containing 10 and 20 members are 2 and 3 respectively measured from their common mean is 5. The standard deviation for the whole set of 30 members is

The mean of 5 observations is 5 and their variance is 124. If three of the observationsare 1,2 and 6, then the mean deviation from the mean of the data is (1)2.4 (b) 2.8 (c) 2.5 (d) 2.6

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