सदिश ` hati +hatj +hatk ` और X अक्ष के मध्य कोण ज्ञात कीजिए|

IF the vectors a = hati + hatj + hatk , b = hati - hatj + 2 hatk and c= x hati +(x-2) hatj - hatk are coplanar , then x=

If the vectors bara = hati + hatj + hatk, barb = hati - hatj +2hatk and barc = xhati + (x-2)hatj - hatk are coplanar, then x =

A unit vector coplanar with hati + hatj + 2 hatk and hati + 2 hatj + hatk, and perpendicular to hati + hatj + hatk is : a) ((hatj - hatk )/( sqrt2)) b) ((hati + hatj+ hatk )/( sqrt3)) c) ((hati + hatj + 2 hatk )/( sqrt6)) d) ((hati + 2 hatj + hatk )/( sqrt6))

Vectors Perpendicular to hati - hatj- hatk and in the plane of hati + hatj + hatk and - hati + hatj + hatk are

The vectors lamda hati + hatj + 2 hatk, hati + lamda hatj - hatk and 2 hati - hatj + lamda hatk are coplanar if :