Let `A(2, 3, 5), B(-1, 3, 2), C(lambda, 5, mu)` are the vertices of a triangle and its median through A(I.e.,) AD is equally inclined to the coordinates axes.
Q. Projection of AB onBC is

Let A(2, 3, 5), B(-1, 3, 2), C(lambda, 5, mu) are the vertices of a triangle and its median through A(I.e.,) AD is equally inclined to the coordinates axes. Q. On the basis of the above information answer the following Q. The value of 2lambda-mu is equal to

Let A(2, 3, 5), B(-1, 3, 2), C(lambda, 5, mu) are the vertices of a triangle and its median through A(I.e.,) AD is equally inclined to the coordinates axes. Q. On the basis of the above information answer the following Q. The value of 2lambda-mu is equal to

Let A(2, 3, 5), B(-1, 3, 2), C(lambda, 5, mu) are the vertices of a triangle and its median through A(I.e.,) AD is equally inclined to the coordinates axes. Q. On the basis of the above information answer the following Q. The value of 2lambda-mu is equal to

A=(2,3,5), B(-1,3,2), C=(lambda,5,mu) are the vertices of a triangle. If the median AM is equally inclined to the coordinate axes, then (lambda,mu) =

Let A (2,3,5) , B ( -1,3,2) and C( lambda ,5, mu ) be the vertices of a Delta ABC , If the median through A is equally inclined to the coodinate axes, then

A(2,3,5),B(-1,3,2),C( lambda ,5, mu ) are the vertices of a triangle.If the median through A is equally inclined to co-ordinate axes then the value of 3 lambda-2 mu is

A(3,4,6) , B(0,4,3) , C(a,6,b) are the vertices of a triangle ABC such that the median through A is equally inclined to the coordinate axes,then a+b is

Let A(1, 2, 3), B(0, 0, 1), C(-1, 1, 1) are the vertices of a DeltaABC .The equation of median through C to side AB is