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In a Mathematics examination the numbers...

In a Mathematics examination the numbers scored by 5 candidates are 5 successive odd integers . If their total marks is 185, the highest score is

A

39

B

43

C

41

D

37

Text Solution

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The correct Answer is:
To solve the problem, we need to find the highest score among 5 candidates who scored 5 successive odd integers that sum up to 185. ### Step-by-Step Solution: 1. **Define the Variables**: Let the smallest odd integer be represented as \( x \). The five successive odd integers can then be expressed as: - First integer: \( x \) - Second integer: \( x + 2 \) - Third integer: \( x + 4 \) - Fourth integer: \( x + 6 \) - Fifth integer: \( x + 8 \) 2. **Set Up the Equation**: The total of these five integers is given as 185. Therefore, we can set up the equation: \[ x + (x + 2) + (x + 4) + (x + 6) + (x + 8) = 185 \] 3. **Combine Like Terms**: Simplifying the left side of the equation: \[ x + x + 2 + x + 4 + x + 6 + x + 8 = 185 \] This simplifies to: \[ 5x + 20 = 185 \] 4. **Solve for \( x \)**: To isolate \( x \), subtract 20 from both sides: \[ 5x = 185 - 20 \] \[ 5x = 165 \] Now, divide both sides by 5: \[ x = \frac{165}{5} = 33 \] 5. **Find the Highest Score**: The highest score among the five integers is: \[ x + 8 = 33 + 8 = 41 \] ### Final Answer: The highest score is **41**. ---
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