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In two successive years, 80 and 60 stude...

In two successive years, 80 and 60 students of a school appeared at the final examination of which 60% and 80% passed respectively. The average rate of students passed (in percent) is

A

0.68

B

`68 4/7%`

C

`70%`

D

`72 3/7%`

Text Solution

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The correct Answer is:
To find the average rate of students who passed in two successive years, we can follow these steps: ### Step 1: Calculate the number of students who passed in each year. - For the first year: - Total students = 80 - Percentage passed = 60% - Number of students passed = (60/100) * 80 = 48 students - For the second year: - Total students = 60 - Percentage passed = 80% - Number of students passed = (80/100) * 60 = 48 students ### Step 2: Calculate the total number of students and total number of students passed. - Total students over the two years = 80 + 60 = 140 students - Total students passed over the two years = 48 (from first year) + 48 (from second year) = 96 students ### Step 3: Calculate the average percentage of students who passed. - Average percentage passed = (Total students passed / Total students) * 100 - Average percentage passed = (96 / 140) * 100 ### Step 4: Simplify the calculation. - Average percentage passed = (96 / 140) * 100 = (96 * 100) / 140 = 9600 / 140 - Now, simplify 9600 / 140: - 9600 ÷ 20 = 480 - 140 ÷ 20 = 7 - So, 9600 / 140 = 480 / 7 ### Step 5: Calculate the final result. - 480 / 7 = 68.57 (approximately) - Therefore, the average percentage of students who passed is approximately 68.57%. ### Final Answer: The average rate of students passed (in percent) is approximately **68.57%**.
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