(cot^(2)theta(sec theta-1)+sec^(2)theta^(2)(sin theta-1))/((+-+sin theta))=0

(sec^2 theta-1)/(sec^2 theta)- sin^2 theta=

(tan theta+sec theta-1)(tan theta+1+sec theta)=(2sin theta)/(1-sin theta)

cot^(2) theta ((sec theta -1)/(1+ sin theta ))+ sec^(2) theta ((sin theta -1)/( 1+ sec theta )) =

Prove the following identity : cot^2 theta ((sec theta-1)/(1+sin theta))+ sec^2 theta ((sin theta-1)/(1+sec theta)) =0 .

The trigonometric expression: cot^(2)[(sec theta-1)/(1+sin theta)]+sec^(2)theta[(sin theta-1)/(1+sec theta)] has the value has the

What will be the value of following identities : (cot^(2) theta (sec theta -1))/((1+ sin theta))+ (sec^(2)theta (sintheta -1))/((1+ sec theta))

Prove that: sqrt((1+ sin theta)/(1 - sin theta)) - sec theta = sec theta - sqrt((1 -sin theta)/(1 + sin theta))

Prove that (i) (1- sin theta)/(1+ sin theta)=(sec theta - tan theta )^(2) (ii) ((1+cos theta))/((1- cos theta))= ("cosec" theta + cot theta)^(2)

1-(sin^(2) theta)/(1+cos theta) + (1+cos theta)/(sin theta) - (sin theta)/(1-cos theta) - (1)/(sec theta)=

Prove that: (sec theta-1)/(sec theta+1)=((sin theta)/(1+cos theta))^(2)