" 1."(x^(2)+xy)dy=(x^(3)+y^(2))dx

(x^(2)-2xy)dy+(x^(2)-3xy+2y^(2))dx=0

(x^2y^3+xy)dy=dx

(x^2y^3+xy)dy=dx

(dy)/(dx)=(x^(2)-y^(2))/(xy)

If (2xy-y^(2)-y)dx = (2xy+x-x^(2))dy and y(1)=1 ,then the value of y(-1) is

x^(2)(dy)/(dx)+y^(2)=xy

Which of the following is a homogeneous differential equation? (A) (4x+6y+5)dy-(3y+2x+4)dx= (B) (xy)dx-(x^(3)+y^(3))dy=0 (C) quad y^(2)dx+(x^(2)-xy-y^(2))dy=0

Solve : (dy)/(dx)=(y^(3)+2x^(2)y)/(x^(3)+2xy^(2)) .

(dy)/(dx) = (x^(2)+y^(2))/(xy)