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22^(2)+sqrt(?)=516...

`22^(2)+sqrt(?)=516`

A

1028

B

1024

C

1124

D

1128

Text Solution

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The correct Answer is:
To solve the equation \( 22^2 + \sqrt{?} = 516 \), we will follow these steps: ### Step 1: Calculate \( 22^2 \) First, we need to calculate \( 22^2 \): \[ 22^2 = 484 \] ### Step 2: Substitute \( 22^2 \) into the equation Now we substitute \( 22^2 \) back into the equation: \[ 484 + \sqrt{?} = 516 \] ### Step 3: Isolate \( \sqrt{?} \) Next, we isolate \( \sqrt{?} \) by subtracting \( 484 \) from both sides: \[ \sqrt{?} = 516 - 484 \] \[ \sqrt{?} = 32 \] ### Step 4: Square both sides Now, we square both sides to eliminate the square root: \[ ? = 32^2 \] \[ ? = 1024 \] ### Conclusion Thus, the value of \( ? \) is \( 1024 \).
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ARIHANT SSC-SQUARE ROOT AND CUBE ROOT -FAST TRACK PRACTICE EXERCISE O BASE LEVEL QUESTIONS
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  14. sqrt(6+sqrt(6+sqrt(6+…oo))) is equal to .

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