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If x/4+y/3=10/24 and x/2+y=1, then the ...

If `x/4+y/3=10/24 ` and `x/2+y=1`, then the value of (x+y) is

A

1

B

`3//2`

C

2

D

4

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The correct Answer is:
To solve the equations \( \frac{x}{4} + \frac{y}{3} = \frac{10}{24} \) and \( \frac{x}{2} + y = 1 \), we will follow these steps: ### Step 1: Simplify the first equation The first equation is: \[ \frac{x}{4} + \frac{y}{3} = \frac{10}{24} \] We can simplify \( \frac{10}{24} \) to \( \frac{5}{12} \). So, we rewrite the equation as: \[ \frac{x}{4} + \frac{y}{3} = \frac{5}{12} \] ### Step 2: Clear the fractions To eliminate the fractions, we can multiply the entire equation by the least common multiple (LCM) of the denominators, which is 12: \[ 12 \left(\frac{x}{4}\right) + 12 \left(\frac{y}{3}\right) = 12 \left(\frac{5}{12}\right) \] This simplifies to: \[ 3x + 4y = 5 \] This is our first equation. ### Step 3: Simplify the second equation The second equation is: \[ \frac{x}{2} + y = 1 \] To eliminate the fraction, we multiply the entire equation by 2: \[ 2 \left(\frac{x}{2}\right) + 2y = 2 \cdot 1 \] This simplifies to: \[ x + 2y = 2 \] This is our second equation. ### Step 4: Set up the system of equations Now we have the following system of equations: 1. \( 3x + 4y = 5 \) (Equation 1) 2. \( x + 2y = 2 \) (Equation 2) ### Step 5: Use the elimination method We can multiply Equation 2 by 3 to align the coefficients of \( x \): \[ 3(x + 2y) = 3 \cdot 2 \] This gives us: \[ 3x + 6y = 6 \quad \text{(Equation 3)} \] ### Step 6: Subtract Equation 1 from Equation 3 Now we subtract Equation 1 from Equation 3: \[ (3x + 6y) - (3x + 4y) = 6 - 5 \] This simplifies to: \[ 2y = 1 \] Dividing both sides by 2 gives: \[ y = \frac{1}{2} \] ### Step 7: Substitute \( y \) back to find \( x \) Now we substitute \( y = \frac{1}{2} \) back into Equation 2: \[ x + 2\left(\frac{1}{2}\right) = 2 \] This simplifies to: \[ x + 1 = 2 \] Subtracting 1 from both sides gives: \[ x = 1 \] ### Step 8: Find \( x + y \) Now we can find \( x + y \): \[ x + y = 1 + \frac{1}{2} = \frac{2}{2} + \frac{1}{2} = \frac{3}{2} \] ### Final Answer The value of \( x + y \) is: \[ \frac{3}{2} \] ---
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ARIHANT SSC-LINEAR EQUATIONS-Exercise Basic Level Questions
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